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I’m not quite clear how you’re defining a root in your question, but the equation is true regardless of which function you use to compute the square root.
You could look at the definitions of the functions and argue that $1^2 = 1$, but if that’s what you’re doing, that’s wrong.
$f'(x)$ equals $f(x)$ iff $\forall x$, $f(x) = f(x)$
Again, that’s wrong. $f(x)$ equals $f(x)$ for any $x$ is just another way of saying “the function doesn’t change.”
If you’re talking about a group of functions that form a field, then yes, and that may be true. But if you mean (for example) that $f, g$ are just a pair of functions and $f(x) = g(x)$ for all $x$, then the answers are “no” and “you’re not allowed to do that.”#ifndef __CONFIG_H_
#define __CONFIG_H_
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*/
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