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So, if I execute this code line:
char* param=argv[1];
printf(“Param is %s
“, param);

I get “hello” printed on the console.
Here’s my issue: I don’t know how to get the string form this string.
I tried strcpy(param,”Hello”) but this fails.
EDIT1:
My question is: How can I convert this string to a char*?
EDIT2:
I changed my code to:
char str[] = argv[1];
printf(“Param is %s
“, str);
char* param=str;

But I get a segmentation fault.

A:

You are not allowed to copy from one pointer to another. You need to use strdup() to create a copy of the string, and use that pointer instead.

A:

The data gets copied into a place in memory, but the address of the copy is different.
int main(int argc, char *argv[])
{
char* temp = argv[1]; // copies data into a location
char* charpointer = argv[1]; // address to point to the data
printf(“%s, %s
“, temp, charpointer);
return 0;
}

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After Penn student sent to Admissions office for supporting Hong Kong protests, she was informed she would never receive a degree

Student Alleges Admissions Office Won’t Release Transcript

Anna Walker walks through the Admissions building Tuesday, March 5, 2019. (Photo by Matt Slocum/Getty Images)

A 22-year-old freshman at Penn has been barred from receiving a degree at the Ivy League college over her comments about the Hong Kong protesters.

Anna Walker submitted her application to Penn in May and was initially admitted. According to her application, she posted on Facebook about a police officer that was trying to destroy a mask with Hong Kong protesters.

In response, she said her Instagram and

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A:

You can do this with a combination of in-query string functions and a case expression:
update ddc_revision set
ddc_id = (select distinct(ddc_id) from web_content
where ddc_name = ‘$col_ddc_id’
and web_language = ‘$language_id’)
where ddc_name = ‘$col_ddc_id’
and web_language = ‘$language_id’
and ddc_language = ‘$language_lang’
and ddc_value = ‘$col_ddc_value’

I use $language_lang to denote the name of the currently selected language (this is an easy way to detect if the user has no other choices available). You need to use an IN clause for this query so that you can avoid any T-SQL column aliasing issues. This is a slight adjustment of the logic of your posted UPDATE statement, so it’s a little simpler.
You can use the same technique for any of the other columns you want to update. The advantage is that it makes it really obvious where each column is coming from and what update is being performed.

“According to a new survey by the National Center for Health Statistics, the overall U.S. obesity rate rose to nearly 25 percent in 2014, the highest level on record. Obesity is defined as a body mass index (BMI) of 30 or higher.”

This news comes straight from the CDC. Unfortunately, this is just one more example of the profound health problems in America. As I stated at the beginning of this post: “Obesity is the new AIDS.”

Obesity comes in many forms:

Percentage of New Adults Who Are Overweight or Obese – 24.7% in 2014

Overweight/Obese rate for New Adults – 23.4% in 2014

Percentage of New Children and Teenagers Who Are Overweight or Obese – 18.6% in 2014

Overweight/Obese rate for New Children and Teenagers – 16.7